Base | Representation |
---|---|
bin | 111101000110110010… |
… | …0010101011000101001 |
3 | 110112201020100112211012 |
4 | 1322031210111120221 |
5 | 4122221334143423 |
6 | 140141124313305 |
7 | 12323566465505 |
oct | 1721544253051 |
9 | 415636315735 |
10 | 131224131113 |
11 | 50719667a39 |
12 | 21522842835 |
13 | c4b369787a |
14 | 64cbcbb305 |
15 | 3630569078 |
hex | 1e8d915629 |
131224131113 has 2 divisors, whose sum is σ = 131224131114. Its totient is φ = 131224131112.
The previous prime is 131224131109. The next prime is 131224131133. The reversal of 131224131113 is 311131422131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126203983504 + 5020147609 = 355252^2 + 70853^2 .
It is a cyclic number.
It is not a de Polignac number, because 131224131113 - 22 = 131224131109 is a prime.
It is not a weakly prime, because it can be changed into another prime (131224131133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65612065556 + 65612065557.
It is an arithmetic number, because the mean of its divisors is an integer number (65612065557).
Almost surely, 2131224131113 is an apocalyptic number.
It is an amenable number.
131224131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
131224131113 is an equidigital number, since it uses as much as digits as its factorization.
131224131113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 23.
Adding to 131224131113 its reverse (311131422131), we get a palindrome (442355553244).
The spelling of 131224131113 in words is "one hundred thirty-one billion, two hundred twenty-four million, one hundred thirty-one thousand, one hundred thirteen".
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