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13122413476201 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0010110011100101101001
31201110111020120001102201101
42332331030302303211221
53204444200322214301
643524204210121401
72523030432105511
oct276751462634551
951414216042641
1013122413476201
1141aa203341247
12157b265880261
13742590b992c3
143351b1ad8841
1517b526476701
hexbef4ccb3969

13122413476201 has 2 divisors, whose sum is σ = 13122413476202. Its totient is φ = 13122413476200.

The previous prime is 13122413476157. The next prime is 13122413476223. The reversal of 13122413476201 is 10267431422131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11359562456025 + 1762851020176 = 3370395^2 + 1327724^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122413476201 - 211 = 13122413474153 is a prime.

It is a super-2 number, since 2×131224134762012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13122413426201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206738100 + 6561206738101.

It is an arithmetic number, because the mean of its divisors is an integer number (6561206738101).

Almost surely, 213122413476201 is an apocalyptic number.

It is an amenable number.

13122413476201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122413476201 is an equidigital number, since it uses as much as digits as its factorization.

13122413476201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 37.

Adding to 13122413476201 its reverse (10267431422131), we get a palindrome (23389844898332).

The spelling of 13122413476201 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, four hundred seventy-six thousand, two hundred one".