Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010111101000000100011 |
3 | 1201110111020120010101122111 |
4 | 2332331030302331000203 |
5 | 3204444200324433122 |
6 | 43524204211020151 |
7 | 2523030432326143 |
oct | 276751462750043 |
9 | 51414216111574 |
10 | 13122413514787 |
11 | 41aa203368235 |
12 | 157b26589a657 |
13 | 742590bb0a35 |
14 | 3351b1b08923 |
15 | 17b526482d77 |
hex | bef4ccbd023 |
13122413514787 has 2 divisors, whose sum is σ = 13122413514788. Its totient is φ = 13122413514786.
The previous prime is 13122413514781. The next prime is 13122413514811. The reversal of 13122413514787 is 78741531422131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122413514787 - 243 = 4326320492579 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13122413514787.
It is not a weakly prime, because it can be changed into another prime (13122413514781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206757393 + 6561206757394.
It is an arithmetic number, because the mean of its divisors is an integer number (6561206757394).
Almost surely, 213122413514787 is an apocalyptic number.
13122413514787 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122413514787 is an equidigital number, since it uses as much as digits as its factorization.
13122413514787 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1128960, while the sum is 49.
The spelling of 13122413514787 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fourteen thousand, seven hundred eighty-seven".
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