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13122413514787 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0010111101000000100011
31201110111020120010101122111
42332331030302331000203
53204444200324433122
643524204211020151
72523030432326143
oct276751462750043
951414216111574
1013122413514787
1141aa203368235
12157b26589a657
13742590bb0a35
143351b1b08923
1517b526482d77
hexbef4ccbd023

13122413514787 has 2 divisors, whose sum is σ = 13122413514788. Its totient is φ = 13122413514786.

The previous prime is 13122413514781. The next prime is 13122413514811. The reversal of 13122413514787 is 78741531422131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13122413514787 - 243 = 4326320492579 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13122413514787.

It is not a weakly prime, because it can be changed into another prime (13122413514781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206757393 + 6561206757394.

It is an arithmetic number, because the mean of its divisors is an integer number (6561206757394).

Almost surely, 213122413514787 is an apocalyptic number.

13122413514787 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122413514787 is an equidigital number, since it uses as much as digits as its factorization.

13122413514787 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1128960, while the sum is 49.

The spelling of 13122413514787 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fourteen thousand, seven hundred eighty-seven".