Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0100110011100100011110 |
3 | 1201110111020121001001210200 |
4 | 2332331030310303210132 |
5 | 3204444200441003124 |
6 | 43524204225244330 |
7 | 2523030436421025 |
oct | 276751464634436 |
9 | 51414217031720 |
10 | 13122414000414 |
11 | 41aa20366a084 |
12 | 157b265a936a6 |
13 | 742591020aa4 |
14 | 3351b1bd38bc |
15 | 17b52652bbc9 |
hex | bef4cd3391e |
13122414000414 has 12 divisors (see below), whose sum is σ = 28431897000936. Its totient is φ = 4374138000132.
The previous prime is 13122414000391. The next prime is 13122414000431. The reversal of 13122414000414 is 41400041422131.
13122414000414 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 241 + 4 + 0 + 0 + 0 + 414 = 666.
It is a super-2 number, since 2×131224140004142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 364511499994 + ... + 364511500029.
It is an arithmetic number, because the mean of its divisors is an integer number (2369324750078).
Almost surely, 213122414000414 is an apocalyptic number.
13122414000414 is an abundant number, since it is smaller than the sum of its proper divisors (15309483000522).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122414000414 is a wasteful number, since it uses less digits than its factorization.
13122414000414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 729023000031 (or 729023000028 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 13122414000414 its reverse (41400041422131), we get a palindrome (54522455422545).
The spelling of 13122414000414 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, four hundred fourteen", and thus it is an aban number.
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