13122422144041 has 8 divisors (see below), whose sum is σ = 14999172462720. Its totient is φ = 11246201471328.

The previous prime is 13122422144021. The next prime is 13122422144047. The reversal of 13122422144041 is 14044122422131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13122422144041 - 2¹⁵ = 13122422111273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13122422143994 and 13122422144012.

It is not an unprimeable number, because it can be changed into a prime (13122422144047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132358396 + ... + 132457501.

It is an arithmetic number, because the mean of its divisors is an integer number (1874896557840).

Almost surely, 2^{13122422144041} is an apocalyptic number.

It is an amenable number.

13122422144041 is a deficient number, since it is larger than the sum of its proper divisors (1876750318679).

13122422144041 is an equidigital number, since it uses as much as digits as its factorization.

13122422144041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264822983.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 13122422144041 its reverse (14044122422131), we get a palindrome (27166544566172).

The spelling of 13122422144041 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twenty-two million, one hundred forty-four thousand, forty-one".