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13122422144040 = 233511102125313847
BaseRepresentation
bin1011111011110100110101…
…0011110111110000101000
31201110111021011100210202110
42332331031103313300220
53204444210032102130
643524205120002320
72523030565556256
oct276751523676050
951414234323673
1013122422144040
1141aa208221550
12157b2687603a0
137425929126c1
143351b2d135d6
1517b5270d9ab0
hexbef4d4f7c28

13122422144040 has 256 divisors, whose sum is σ = 43016335165440. Its totient is φ = 3175996032000.

The previous prime is 13122422144021. The next prime is 13122422144047. The reversal of 13122422144040 is 4044122422131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13122422143989 and 13122422144007.

It is not an unprimeable number, because it can be changed into a prime (13122422144047) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3411077397 + ... + 3411081243.

It is an arithmetic number, because the mean of its divisors is an integer number (168032559240).

Almost surely, 213122422144040 is an apocalyptic number.

13122422144040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13122422144040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21508167582720).

13122422144040 is an abundant number, since it is smaller than the sum of its proper divisors (29893913021400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13122422144040 is a wasteful number, since it uses less digits than its factorization.

13122422144040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7424 (or 7420 counting only the distinct ones).

The product of its (nonzero) digits is 12288, while the sum is 30.

Adding to 13122422144040 its reverse (4044122422131), we get a palindrome (17166544566171).

The spelling of 13122422144040 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twenty-two million, one hundred forty-four thousand, forty".