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13122422144021 is a prime number
BaseRepresentation
bin1011111011110100110101…
…0011110111110000010101
31201110111021011100210201202
42332331031103313300111
53204444210032102041
643524205120002245
72523030565556231
oct276751523676025
951414234323652
1013122422144021
1141aa208221533
12157b268760385
137425929126a8
143351b2d135c1
1517b5270d9a9b
hexbef4d4f7c15

13122422144021 has 2 divisors, whose sum is σ = 13122422144022. Its totient is φ = 13122422144020.

The previous prime is 13122422143993. The next prime is 13122422144047. The reversal of 13122422144021 is 12044122422131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12986437468900 + 135984675121 = 3603670^2 + 368761^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122422144021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122422144621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561211072010 + 6561211072011.

It is an arithmetic number, because the mean of its divisors is an integer number (6561211072011).

Almost surely, 213122422144021 is an apocalyptic number.

It is an amenable number.

13122422144021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122422144021 is an equidigital number, since it uses as much as digits as its factorization.

13122422144021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 13122422144021 its reverse (12044122422131), we get a palindrome (25166544566152).

The spelling of 13122422144021 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twenty-two million, one hundred forty-four thousand, twenty-one".