Base | Representation |
---|---|
bin | 1011111011110100111010… |
… | …1011001100001110101111 |
3 | 1201110111022202102202110010 |
4 | 2332331032223030032233 |
5 | 3204444231412100130 |
6 | 43524211254344303 |
7 | 2523031264254123 |
oct | 276751653141657 |
9 | 51414282382403 |
10 | 13122445034415 |
11 | 41aa21a136412 |
12 | 157b27435b093 |
13 | 7425975985c2 |
14 | 3351b5d91583 |
15 | 17b52910c0b0 |
hex | bef4eacc3af |
13122445034415 has 64 divisors (see below), whose sum is σ = 21782026690560. Its totient is φ = 6738004116480.
The previous prime is 13122445034383. The next prime is 13122445034431. The reversal of 13122445034415 is 51443054422131.
It is not a de Polignac number, because 13122445034415 - 25 = 13122445034383 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 246325612 + ... + 246378878.
It is an arithmetic number, because the mean of its divisors is an integer number (340344167040).
Almost surely, 213122445034415 is an apocalyptic number.
13122445034415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13122445034415 is a deficient number, since it is larger than the sum of its proper divisors (8659581656145).
13122445034415 is a wasteful number, since it uses less digits than its factorization.
13122445034415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54912.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 13122445034415 its reverse (51443054422131), we get a palindrome (64565499456546).
The spelling of 13122445034415 in words is "thirteen trillion, one hundred twenty-two billion, four hundred forty-five million, thirty-four thousand, four hundred fifteen".
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