Base | Representation |
---|---|
bin | 10011000110000111111… |
… | …110110100001001000011 |
3 | 11122110010201010211200212 |
4 | 103012013332310021003 |
5 | 132444440040302224 |
6 | 2442500534504335 |
7 | 163543455332054 |
oct | 23060776641103 |
9 | 4573121124625 |
10 | 1312246415939 |
11 | 46657a9897a8 |
12 | 1923a48050ab |
13 | 9698a3181c4 |
14 | 47727bcc72b |
15 | 2420411cd0e |
hex | 13187fb4243 |
1312246415939 has 2 divisors, whose sum is σ = 1312246415940. Its totient is φ = 1312246415938.
The previous prime is 1312246415927. The next prime is 1312246415983. The reversal of 1312246415939 is 9395146422131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9395146422131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312246415939 is a prime.
It is a super-2 number, since 2×13122464159392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312246015939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656123207969 + 656123207970.
It is an arithmetic number, because the mean of its divisors is an integer number (656123207970).
Almost surely, 21312246415939 is an apocalyptic number.
1312246415939 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312246415939 is an equidigital number, since it uses as much as digits as its factorization.
1312246415939 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 50.
The spelling of 1312246415939 in words is "one trillion, three hundred twelve billion, two hundred forty-six million, four hundred fifteen thousand, nine hundred thirty-nine".
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