13122655140127 has 12 divisors (see below), whose sum is σ = 14209860930240. Its totient is φ = 12113116187328.

The previous prime is 13122655140121. The next prime is 13122655140139. The reversal of 13122655140127 is 72104155622131.

It is a happy number.

It is not a de Polignac number, because 13122655140127 - 2¹¹ = 13122655138079 is a prime.

It is a super-3 number, since 3×13122655140127³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13122655140127.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13122655140121) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25186603 + ... + 25702339.

It is an arithmetic number, because the mean of its divisors is an integer number (1184155077520).

Almost surely, 2^{13122655140127} is an apocalyptic number.

13122655140127 is a deficient number, since it is larger than the sum of its proper divisors (1087205790113).

13122655140127 is a wasteful number, since it uses less digits than its factorization.

13122655140127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 666322 (or 666309 counting only the distinct ones).

The product of its (nonzero) digits is 100800, while the sum is 40.

The spelling of 13122655140127 in words is "thirteen trillion, one hundred twenty-two billion, six hundred fifty-five million, one hundred forty thousand, one hundred twenty-seven".