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131230123122257 is a prime number
BaseRepresentation
bin11101110101101001100100…
…110111110101111001010001
3122012122110212220200120002222
4131311221210313311321101
5114200033243004403012
61143034141501350425
736433030533550415
oct3565514467657121
9565573786616088
10131230123122257
11388a5423381985
121287533a868415
13582bc418b3093
142459801220d45
1510288e3acd972
hex775a64df5e51

131230123122257 has 2 divisors, whose sum is σ = 131230123122258. Its totient is φ = 131230123122256.

The previous prime is 131230123122253. The next prime is 131230123122347. The reversal of 131230123122257 is 752221321032131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107617365506641 + 23612757615616 = 10373879^2 + 4859296^2 .

It is an emirp because it is prime and its reverse (752221321032131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131230123122257 - 22 = 131230123122253 is a prime.

It is not a weakly prime, because it can be changed into another prime (131230123122253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615061561128 + 65615061561129.

It is an arithmetic number, because the mean of its divisors is an integer number (65615061561129).

Almost surely, 2131230123122257 is an apocalyptic number.

It is an amenable number.

131230123122257 is a deficient number, since it is larger than the sum of its proper divisors (1).

131230123122257 is an equidigital number, since it uses as much as digits as its factorization.

131230123122257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 131230123122257 its reverse (752221321032131), we get a palindrome (883451444154388).

The spelling of 131230123122257 in words is "one hundred thirty-one trillion, two hundred thirty billion, one hundred twenty-three million, one hundred twenty-two thousand, two hundred fifty-seven".