1312304703 has 4 divisors (see below), whose sum is σ = 1749739608. Its totient is φ = 874869800.

The previous prime is 1312304701. The next prime is 1312304713. The reversal of 1312304703 is 3074032131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312304703 - 2¹ = 1312304701 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312304701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218717448 + ... + 218717453.

It is an arithmetic number, because the mean of its divisors is an integer number (437434902).

Almost surely, 2^1312304703 is an apocalyptic number.

1312304703 is a deficient number, since it is larger than the sum of its proper divisors (437434905).

1312304703 is an equidigital number, since it uses as much as digits as its factorization.

1312304703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437434904.

The product of its (nonzero) digits is 1512, while the sum is 24.

The square root of 1312304703 is about 36225.7464105296. The cubic root of 1312304703 is about 1094.8254770751.

Adding to 1312304703 its reverse (3074032131), we get a palindrome (4386336834).

The spelling of 1312304703 in words is "one billion, three hundred twelve million, three hundred four thousand, seven hundred three".