Base | Representation |
---|---|
bin | 10011000110001011111… |
… | …001000010111000010011 |
3 | 11122110022021120110222222 |
4 | 103012023321002320103 |
5 | 133000103333343212 |
6 | 2442511240451255 |
7 | 163545213025112 |
oct | 23061371027023 |
9 | 4573267513888 |
10 | 1312312012307 |
11 | 466603a1227a |
12 | 192402779b2b |
13 | 9699aaa451a |
14 | 477327c5c79 |
15 | 24209c78c72 |
hex | 1318be42e13 |
1312312012307 has 2 divisors, whose sum is σ = 1312312012308. Its totient is φ = 1312312012306.
The previous prime is 1312312012247. The next prime is 1312312012409. The reversal of 1312312012307 is 7032102132131.
It is a weak prime.
It is an emirp because it is prime and its reverse (7032102132131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312312012307 - 212 = 1312312008211 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312312015307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656156006153 + 656156006154.
It is an arithmetic number, because the mean of its divisors is an integer number (656156006154).
Almost surely, 21312312012307 is an apocalyptic number.
1312312012307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312312012307 is an equidigital number, since it uses as much as digits as its factorization.
1312312012307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1312312012307 its reverse (7032102132131), we get a palindrome (8344414144438).
The spelling of 1312312012307 in words is "one trillion, three hundred twelve billion, three hundred twelve million, twelve thousand, three hundred seven".
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