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13123204431313 is a prime number
BaseRepresentation
bin1011111011110111101111…
…1100000011110111010001
31201110120021200101010011011
42332331323330003313101
53210002310313300223
643524414503050521
72523056145111214
oct276757374036721
951416250333134
1013123204431313
1141aa579864559
12157b446740a41
13742688a03292
14335248b8b77b
1517b570b1380d
hexbef7bf03dd1

13123204431313 has 2 divisors, whose sum is σ = 13123204431314. Its totient is φ = 13123204431312.

The previous prime is 13123204431223. The next prime is 13123204431371. The reversal of 13123204431313 is 31313440232131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13075253504784 + 47950926529 = 3615972^2 + 218977^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123204431313 - 233 = 13114614496721 is a prime.

It is not a weakly prime, because it can be changed into another prime (13123204431013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561602215656 + 6561602215657.

It is an arithmetic number, because the mean of its divisors is an integer number (6561602215657).

Almost surely, 213123204431313 is an apocalyptic number.

It is an amenable number.

13123204431313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123204431313 is an equidigital number, since it uses as much as digits as its factorization.

13123204431313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13123204431313 its reverse (31313440232131), we get a palindrome (44436644663444).

The spelling of 13123204431313 in words is "thirteen trillion, one hundred twenty-three billion, two hundred four million, four hundred thirty-one thousand, three hundred thirteen".