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131232140421281 is a prime number
BaseRepresentation
bin11101110101101011011101…
…000111001110100010100001
3122012122200002111120222010122
4131311223131013032202201
5114200101410421440111
61143035114003210025
736433131530401604
oct3565533507164241
9565580074528118
10131232140421281
11388a6269064559
1212875802376915
13582c1a3806343
14245995310033b
1510289b0c5bcdb
hex775add1ce8a1

131232140421281 has 2 divisors, whose sum is σ = 131232140421282. Its totient is φ = 131232140421280.

The previous prime is 131232140421271. The next prime is 131232140421377. The reversal of 131232140421281 is 182124041232131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78966238827025 + 52265901594256 = 8886295^2 + 7229516^2 .

It is a cyclic number.

It is not a de Polignac number, because 131232140421281 - 242 = 126834093910177 is a prime.

It is a super-2 number, since 2×1312321404212812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131232140421271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616070210640 + 65616070210641.

It is an arithmetic number, because the mean of its divisors is an integer number (65616070210641).

Almost surely, 2131232140421281 is an apocalyptic number.

It is an amenable number.

131232140421281 is a deficient number, since it is larger than the sum of its proper divisors (1).

131232140421281 is an equidigital number, since it uses as much as digits as its factorization.

131232140421281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 35.

The spelling of 131232140421281 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, one hundred forty million, four hundred twenty-one thousand, two hundred eighty-one".