Base | Representation |
---|---|
bin | 111101000111000001… |
… | …1111001001010111001 |
3 | 110112201210220212022002 |
4 | 1322032003321022321 |
5 | 4122230443413103 |
6 | 140142021510345 |
7 | 12324030013244 |
oct | 1721603711271 |
9 | 415653825262 |
10 | 131232404153 |
11 | 507232a8664 |
12 | 215255723b5 |
13 | c4b5303366 |
14 | 64cd03225b |
15 | 3631150488 |
hex | 1e8e0f92b9 |
131232404153 has 2 divisors, whose sum is σ = 131232404154. Its totient is φ = 131232404152.
The previous prime is 131232404137. The next prime is 131232404161. The reversal of 131232404153 is 351404232131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 82767262249 + 48465141904 = 287693^2 + 220148^2 .
It is a cyclic number.
It is not a de Polignac number, because 131232404153 - 24 = 131232404137 is a prime.
It is not a weakly prime, because it can be changed into another prime (131232404113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616202076 + 65616202077.
It is an arithmetic number, because the mean of its divisors is an integer number (65616202077).
Almost surely, 2131232404153 is an apocalyptic number.
It is an amenable number.
131232404153 is a deficient number, since it is larger than the sum of its proper divisors (1).
131232404153 is an equidigital number, since it uses as much as digits as its factorization.
131232404153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 131232404153 its reverse (351404232131), we get a palindrome (482636636284).
The spelling of 131232404153 in words is "one hundred thirty-one billion, two hundred thirty-two million, four hundred four thousand, one hundred fifty-three".
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