Base | Representation |
---|---|
bin | 11101110101101011101101… |
… | …010011101001100111111001 |
3 | 122012122200210102211100122202 |
4 | 131311223231103221213321 |
5 | 114200102440000112101 |
6 | 1143035200550355545 |
7 | 36433141336631114 |
oct | 3565535523514771 |
9 | 565580712740582 |
10 | 131232412113401 |
11 | 388a63984638a5 |
12 | 1287587935bbb5 |
13 | 582c217ba2401 |
14 | 245997b22557b |
15 | 10289c9a2836b |
hex | 775aed4e99f9 |
131232412113401 has 2 divisors, whose sum is σ = 131232412113402. Its totient is φ = 131232412113400.
The previous prime is 131232412113389. The next prime is 131232412113409. The reversal of 131232412113401 is 104311214232131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130435586305600 + 796825807801 = 11420840^2 + 892651^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131232412113401 is a prime.
It is not a weakly prime, because it can be changed into another prime (131232412113409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616206056700 + 65616206056701.
It is an arithmetic number, because the mean of its divisors is an integer number (65616206056701).
Almost surely, 2131232412113401 is an apocalyptic number.
It is an amenable number.
131232412113401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131232412113401 is an equidigital number, since it uses as much as digits as its factorization.
131232412113401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 131232412113401 its reverse (104311214232131), we get a palindrome (235543626345532).
The spelling of 131232412113401 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, four hundred twelve million, one hundred thirteen thousand, four hundred one".
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