Base | Representation |
---|---|
bin | 10011000110001101000… |
… | …010010101000110010101 |
3 | 11122110100121201111201121 |
4 | 103012031002111012111 |
5 | 133000123243122240 |
6 | 2442513204323541 |
7 | 163545535230214 |
oct | 23061502250625 |
9 | 4573317644647 |
10 | 1312331223445 |
11 | 466613843950 |
12 | 1924090a35b1 |
13 | 969a1a6c868 |
14 | 4773518707b |
15 | 2420b7c104a |
hex | 1318d095195 |
1312331223445 has 16 divisors (see below), whose sum is σ = 1719830321280. Its totient is φ = 953384126400.
The previous prime is 1312331223443. The next prime is 1312331223523. The reversal of 1312331223445 is 5443221332131.
It is not a de Polignac number, because 1312331223445 - 21 = 1312331223443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312331223445.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312331223443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12931266 + ... + 13032355.
It is an arithmetic number, because the mean of its divisors is an integer number (107489395080).
Almost surely, 21312331223445 is an apocalyptic number.
It is an amenable number.
1312331223445 is a deficient number, since it is larger than the sum of its proper divisors (407499097835).
1312331223445 is a wasteful number, since it uses less digits than its factorization.
1312331223445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25964556.
The product of its digits is 51840, while the sum is 34.
Adding to 1312331223445 its reverse (5443221332131), we get a palindrome (6755552555576).
The spelling of 1312331223445 in words is "one trillion, three hundred twelve billion, three hundred thirty-one million, two hundred twenty-three thousand, four hundred forty-five".
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