Base | Representation |
---|---|
bin | 11101110101101100010111… |
… | …101100111111111010111101 |
3 | 122012122202122000020112100220 |
4 | 131311230113230333322331 |
5 | 114200110414042321110 |
6 | 1143035355320011553 |
7 | 36433165064525064 |
oct | 3565542754777275 |
9 | 565582560215326 |
10 | 131233123401405 |
11 | 388a6722a13023 |
12 | 12875a37600bb9 |
13 | 582c2cc36469c |
14 | 2459a0789b1db |
15 | 1028a1c1ca370 |
hex | 775b17b3febd |
131233123401405 has 32 divisors (see below), whose sum is σ = 210409321382784. Its totient is φ = 69845681907456.
The previous prime is 131233123401337. The next prime is 131233123401421. The reversal of 131233123401405 is 504104321332131.
It is not a de Polignac number, because 131233123401405 - 213 = 131233123393213 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13052259 + ... + 20804511.
It is an arithmetic number, because the mean of its divisors is an integer number (6575291293212).
Almost surely, 2131233123401405 is an apocalyptic number.
131233123401405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131233123401405 is a deficient number, since it is larger than the sum of its proper divisors (79176197981379).
131233123401405 is a wasteful number, since it uses less digits than its factorization.
131233123401405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7754605.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 131233123401405 its reverse (504104321332131), we get a palindrome (635337444733536).
The spelling of 131233123401405 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred twenty-three million, four hundred one thousand, four hundred five".
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