13123332450049 has 2 divisors, whose sum is σ = 13123332450050. Its totient is φ = 13123332450048.

The previous prime is 13123332450037. The next prime is 13123332450149. The reversal of 13123332450049 is 94005423332131.

13123332450049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12387971319025 + 735361131024 = 3519655^2 + 857532^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123332450049 - 2⁷ = 13123332449921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13123332449993 and 13123332450020.

It is not a weakly prime, because it can be changed into another prime (13123332450149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561666225024 + 6561666225025.

It is an arithmetic number, because the mean of its divisors is an integer number (6561666225025).

Almost surely, 2^{13123332450049} is an apocalyptic number.

It is an amenable number.

13123332450049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123332450049 is an equidigital number, since it uses as much as digits as its factorization.

13123332450049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 40.

The spelling of 13123332450049 in words is "thirteen trillion, one hundred twenty-three billion, three hundred thirty-two million, four hundred fifty thousand, forty-nine".