Base | Representation |
---|---|
bin | 11101110101101101001101… |
… | …011001110001101011100001 |
3 | 122012122211221210111112210202 |
4 | 131311231031121301223201 |
5 | 114200114240212111001 |
6 | 1143040024542034545 |
7 | 36433226314360643 |
oct | 3565551531615341 |
9 | 565584853445722 |
10 | 131234024332001 |
11 | 388a7045520568 |
12 | 12876049278a55 |
13 | 582c413bc5806 |
14 | 2459a913ba893 |
15 | 1028a7133c96b |
hex | 775b4d671ae1 |
131234024332001 has 2 divisors, whose sum is σ = 131234024332002. Its totient is φ = 131234024332000.
The previous prime is 131234024331983. The next prime is 131234024332031. The reversal of 131234024332001 is 100233420432131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106712205625600 + 24521818706401 = 10330160^2 + 4951951^2 .
It is a cyclic number.
It is not a de Polignac number, because 131234024332001 - 210 = 131234024330977 is a prime.
It is not a weakly prime, because it can be changed into another prime (131234024332031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65617012166000 + 65617012166001.
It is an arithmetic number, because the mean of its divisors is an integer number (65617012166001).
Almost surely, 2131234024332001 is an apocalyptic number.
It is an amenable number.
131234024332001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131234024332001 is an equidigital number, since it uses as much as digits as its factorization.
131234024332001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 131234024332001 its reverse (100233420432131), we get a palindrome (231467444764132).
The spelling of 131234024332001 in words is "one hundred thirty-one trillion, two hundred thirty-four billion, twenty-four million, three hundred thirty-two thousand, one".
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