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13123410225454 = 26561705112727
BaseRepresentation
bin1011111011111000100000…
…1101000110100100101110
31201110120211000121112122101
42332332020031012210232
53210003221004203304
643524451134005314
72523064224250144
oct276761015064456
951416730545571
1013123410225454
1141aa674a44761
12157b4a364683a
137426bc538969
1433526823b594
1517b583c148a4
hexbef8834692e

13123410225454 has 4 divisors (see below), whose sum is σ = 19685115338184. Its totient is φ = 6561705112726.

The previous prime is 13123410225451. The next prime is 13123410225461. The reversal of 13123410225454 is 45452201432131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131234102254542 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123410225451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280852556362 + ... + 3280852556365.

It is an arithmetic number, because the mean of its divisors is an integer number (4921278834546).

Almost surely, 213123410225454 is an apocalyptic number.

13123410225454 is a deficient number, since it is larger than the sum of its proper divisors (6561705112730).

13123410225454 is an equidigital number, since it uses as much as digits as its factorization.

13123410225454 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6561705112729.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 13123410225454 its reverse (45452201432131), we get a palindrome (58575611657585).

The spelling of 13123410225454 in words is "thirteen trillion, one hundred twenty-three billion, four hundred ten million, two hundred twenty-five thousand, four hundred fifty-four".

Divisors: 1 2 6561705112727 13123410225454