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13123443340342 = 26561721670171
BaseRepresentation
bin1011111011111000101000…
…1011011011010000110110
31201110120220022220221201201
42332332022023123100312
53210003302443342332
643524454315443114
72523065105601046
oct276761213332066
951416808827651
1013123443340342
1141aa691702435
12157b4b275649a
137426c636167a
1433526c7bb726
1517b586aa65e7
hexbef8a2db436

13123443340342 has 4 divisors (see below), whose sum is σ = 19685165010516. Its totient is φ = 6561721670170.

The previous prime is 13123443340327. The next prime is 13123443340409. The reversal of 13123443340342 is 24304334432131.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280860835084 + ... + 3280860835087.

It is an arithmetic number, because the mean of its divisors is an integer number (4921291252629).

Almost surely, 213123443340342 is an apocalyptic number.

13123443340342 is a deficient number, since it is larger than the sum of its proper divisors (6561721670174).

13123443340342 is an equidigital number, since it uses as much as digits as its factorization.

13123443340342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6561721670173.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 13123443340342 its reverse (24304334432131), we get a palindrome (37427777772473).

The spelling of 13123443340342 in words is "thirteen trillion, one hundred twenty-three billion, four hundred forty-three million, three hundred forty thousand, three hundred forty-two".

Divisors: 1 2 6561721670171 13123443340342