Base | Representation |
---|---|
bin | 10011000110001110010… |
… | …001101111100111011010 |
3 | 11122110102001220011122020 |
4 | 103012032101233213122 |
5 | 133000144110311214 |
6 | 2442515230435310 |
7 | 163546210204110 |
oct | 23061621574732 |
9 | 4573361804566 |
10 | 1312352041434 |
11 | 4666245727a5 |
12 | 192414062b36 |
13 | 969a617b3b5 |
14 | 47737c45ab0 |
15 | 2420d5344a9 |
hex | 1318e46f9da |
1312352041434 has 64 divisors (see below), whose sum is σ = 3063111453696. Its totient is φ = 367095193344.
The previous prime is 1312352041423. The next prime is 1312352041447. The reversal of 1312352041434 is 4341402532131.
It is a junction number, because it is equal to n+sod(n) for n = 1312352041395 and 1312352041404.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 971887 + ... + 1889250.
It is an arithmetic number, because the mean of its divisors is an integer number (47861116464).
Almost surely, 21312352041434 is an apocalyptic number.
1312352041434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1312352041434 is an abundant number, since it is smaller than the sum of its proper divisors (1750759412262).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312352041434 is a wasteful number, since it uses less digits than its factorization.
1312352041434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2861379.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 1312352041434 its reverse (4341402532131), we get a palindrome (5653754573565).
The spelling of 1312352041434 in words is "one trillion, three hundred twelve billion, three hundred fifty-two million, forty-one thousand, four hundred thirty-four".
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