1312400433433 has 2 divisors, whose sum is σ = 1312400433434. Its totient is φ = 1312400433432.

The previous prime is 1312400433403. The next prime is 1312400433451. The reversal of 1312400433433 is 3343340042131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 892254046464 + 420146386969 = 944592^2 + 648187^2 .

It is an emirp because it is prime and its reverse (3343340042131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312400433433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312400433395 and 1312400433404.

It is not a weakly prime, because it can be changed into another prime (1312400433403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656200216716 + 656200216717.

It is an arithmetic number, because the mean of its divisors is an integer number (656200216717).

Almost surely, 2^{1312400433433} is an apocalyptic number.

It is an amenable number.

1312400433433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312400433433 is an equidigital number, since it uses as much as digits as its factorization.

1312400433433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1312400433433 its reverse (3343340042131), we get a palindrome (4655740475564).

The spelling of 1312400433433 in words is "one trillion, three hundred twelve billion, four hundred million, four hundred thirty-three thousand, four hundred thirty-three".