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13124105553641 is a prime number
BaseRepresentation
bin1011111011111011000110…
…1001100100011011101001
31201110122121110222212121012
42332332301221210123221
53210011132010204031
643525044133153305
72523120366403055
oct276766151443351
951418543885535
1013124105553641
1141aa9a1493055
12157b65848b835
137427a0600764
143352d271ac65
1517b5c4cb2b2b
hexbefb1a646e9

13124105553641 has 2 divisors, whose sum is σ = 13124105553642. Its totient is φ = 13124105553640.

The previous prime is 13124105553563. The next prime is 13124105553653. The reversal of 13124105553641 is 14635550142131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8411038232041 + 4713067321600 = 2900179^2 + 2170960^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124105553641 - 210 = 13124105552617 is a prime.

It is a super-2 number, since 2×131241055536412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13124105553661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562052776820 + 6562052776821.

It is an arithmetic number, because the mean of its divisors is an integer number (6562052776821).

Almost surely, 213124105553641 is an apocalyptic number.

It is an amenable number.

13124105553641 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124105553641 is an equidigital number, since it uses as much as digits as its factorization.

13124105553641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 41.

Adding to 13124105553641 its reverse (14635550142131), we get a palindrome (27759655695772).

The spelling of 13124105553641 in words is "thirteen trillion, one hundred twenty-four billion, one hundred five million, five hundred fifty-three thousand, six hundred forty-one".