Base | Representation |
---|---|
bin | 10011000110010001111… |
… | …100010110011011100011 |
3 | 11122110120100121201201020 |
4 | 103012101330112123203 |
5 | 133000310331321430 |
6 | 2442525304540523 |
7 | 163550555021304 |
oct | 23062174263343 |
9 | 4573510551636 |
10 | 1312413542115 |
11 | 466656259105 |
12 | 192430781743 |
13 | 969b5b32430 |
14 | 477420947ab |
15 | 24213b31b10 |
hex | 13191f166e3 |
1312413542115 has 64 divisors (see below), whose sum is σ = 2394774813312. Its totient is φ = 608012697600.
The previous prime is 1312413542093. The next prime is 1312413542159. The reversal of 1312413542115 is 5112453142131.
It is not a de Polignac number, because 1312413542115 - 27 = 1312413541987 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 25038535 + ... + 25090895.
It is an arithmetic number, because the mean of its divisors is an integer number (37418356458).
Almost surely, 21312413542115 is an apocalyptic number.
1312413542115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1312413542115 is a deficient number, since it is larger than the sum of its proper divisors (1082361271197).
1312413542115 is a wasteful number, since it uses less digits than its factorization.
1312413542115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59960.
The product of its digits is 14400, while the sum is 33.
Adding to 1312413542115 its reverse (5112453142131), we get a palindrome (6424866684246).
The spelling of 1312413542115 in words is "one trillion, three hundred twelve billion, four hundred thirteen million, five hundred forty-two thousand, one hundred fifteen".
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