Base | Representation |
---|---|
bin | 11101110101110100101010… |
… | …001111110010001000010001 |
3 | 122012200121121100010100221012 |
4 | 131311310222033302020101 |
5 | 114200232131224210213 |
6 | 1143043430444140305 |
7 | 36433631466246620 |
oct | 3565645217621021 |
9 | 565617540110835 |
10 | 131242024444433 |
11 | 388aa480365431 |
12 | 12877700537695 |
13 | 58300ba477b56 |
14 | 245a20dab36b7 |
15 | 1028d8d85b4a8 |
hex | 775d2a3f2211 |
131242024444433 has 48 divisors (see below), whose sum is σ = 153684822282240. Its totient is φ = 109773847572480.
The previous prime is 131242024444423. The next prime is 131242024444457. The reversal of 131242024444433 is 334444420242131.
It is not a de Polignac number, because 131242024444433 - 214 = 131242024428049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131242024444423) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1723904513 + ... + 1723980641.
It is an arithmetic number, because the mean of its divisors is an integer number (3201767130880).
Almost surely, 2131242024444433 is an apocalyptic number.
It is an amenable number.
131242024444433 is a deficient number, since it is larger than the sum of its proper divisors (22442797837807).
131242024444433 is a wasteful number, since it uses less digits than its factorization.
131242024444433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76638 (or 76507 counting only the distinct ones).
The product of its (nonzero) digits is 884736, while the sum is 41.
Adding to 131242024444433 its reverse (334444420242131), we get a palindrome (465686444686564).
The spelling of 131242024444433 in words is "one hundred thirty-one trillion, two hundred forty-two billion, twenty-four million, four hundred forty-four thousand, four hundred thirty-three".
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