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13124214442147 is a prime number
BaseRepresentation
bin1011111011111011100000…
…1000111100100010100011
31201110122220001212222112211
42332332320020330202203
53210011342344122042
643525103023102551
72523123161055214
oct276767010744243
951418801788484
1013124214442147
1141aaa479a5656
12157b688a41a57
137427ba036c23
14335302d8340b
1517b5ce621017
hexbefb823c8a3

13124214442147 has 2 divisors, whose sum is σ = 13124214442148. Its totient is φ = 13124214442146.

The previous prime is 13124214442123. The next prime is 13124214442181. The reversal of 13124214442147 is 74124441242131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124214442147 is a prime.

It is not a weakly prime, because it can be changed into another prime (13124214443147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562107221073 + 6562107221074.

It is an arithmetic number, because the mean of its divisors is an integer number (6562107221074).

Almost surely, 213124214442147 is an apocalyptic number.

13124214442147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124214442147 is an equidigital number, since it uses as much as digits as its factorization.

13124214442147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172032, while the sum is 40.

Adding to 13124214442147 its reverse (74124441242131), we get a palindrome (87248655684278).

The spelling of 13124214442147 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fourteen million, four hundred forty-two thousand, one hundred forty-seven".