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131242200020947 is a prime number
BaseRepresentation
bin11101110101110100110100…
…101101100011011111010011
3122012200122001120111120122001
4131311310310231203133103
5114200233011201132242
61143043500115254431
736433636030522531
oct3565646455433723
9565618046446561
10131242200020947
11388aa560486694
121287774b2aa417
135830117960492
14245a229139151
151028d9de8deb7
hex775d34b637d3

131242200020947 has 2 divisors, whose sum is σ = 131242200020948. Its totient is φ = 131242200020946.

The previous prime is 131242200020941. The next prime is 131242200021013. The reversal of 131242200020947 is 749020002242131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131242200020947 - 219 = 131242199496659 is a prime.

It is a super-3 number, since 3×1312422000209473 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (131242200020941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621100010473 + 65621100010474.

It is an arithmetic number, because the mean of its divisors is an integer number (65621100010474).

Almost surely, 2131242200020947 is an apocalyptic number.

131242200020947 is a deficient number, since it is larger than the sum of its proper divisors (1).

131242200020947 is an equidigital number, since it uses as much as digits as its factorization.

131242200020947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

The spelling of 131242200020947 in words is "one hundred thirty-one trillion, two hundred forty-two billion, two hundred million, twenty thousand, nine hundred forty-seven".