Base | Representation |
---|---|
bin | 11101110101110100110100… |
… | …101101100011011111010011 |
3 | 122012200122001120111120122001 |
4 | 131311310310231203133103 |
5 | 114200233011201132242 |
6 | 1143043500115254431 |
7 | 36433636030522531 |
oct | 3565646455433723 |
9 | 565618046446561 |
10 | 131242200020947 |
11 | 388aa560486694 |
12 | 1287774b2aa417 |
13 | 5830117960492 |
14 | 245a229139151 |
15 | 1028d9de8deb7 |
hex | 775d34b637d3 |
131242200020947 has 2 divisors, whose sum is σ = 131242200020948. Its totient is φ = 131242200020946.
The previous prime is 131242200020941. The next prime is 131242200021013. The reversal of 131242200020947 is 749020002242131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131242200020947 - 219 = 131242199496659 is a prime.
It is a super-3 number, since 3×1312422000209473 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131242200020941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621100010473 + 65621100010474.
It is an arithmetic number, because the mean of its divisors is an integer number (65621100010474).
Almost surely, 2131242200020947 is an apocalyptic number.
131242200020947 is a deficient number, since it is larger than the sum of its proper divisors (1).
131242200020947 is an equidigital number, since it uses as much as digits as its factorization.
131242200020947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 37.
The spelling of 131242200020947 in words is "one hundred thirty-one trillion, two hundred forty-two billion, two hundred million, twenty thousand, nine hundred forty-seven".
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