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13124255354411 is a prime number
BaseRepresentation
bin1011111011111011101010…
…0101000000111000101011
31201110122222220212112121212
42332332322211000320223
53210011433332320121
643525111044023335
72523124165603025
oct276767245007053
951418886775555
1013124255354411
1141aaa68aa9643
12157b69a691b4b
137427c565ca76
14335308593015
1517b5d300325b
hexbefba940e2b

13124255354411 has 2 divisors, whose sum is σ = 13124255354412. Its totient is φ = 13124255354410.

The previous prime is 13124255354407. The next prime is 13124255354417. The reversal of 13124255354411 is 11445355242131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13124255354411 - 22 = 13124255354407 is a prime.

It is a super-3 number, since 3×131242553544113 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13124255354417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562127677205 + 6562127677206.

It is an arithmetic number, because the mean of its divisors is an integer number (6562127677206).

Almost surely, 213124255354411 is an apocalyptic number.

13124255354411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124255354411 is an equidigital number, since it uses as much as digits as its factorization.

13124255354411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288000, while the sum is 41.

The spelling of 13124255354411 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fifty-five million, three hundred fifty-four thousand, four hundred eleven".