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13124304050131 is a prime number
BaseRepresentation
bin1011111011111011110101…
…1110110001011111010011
31201110200010022111112121001
42332332331132301133103
53210012033314101011
643525115543442431
72523125326526041
oct276767536613723
951420108445531
1013124304050131
1141aaa9353943a
12157b6b2a56417
1374280277c5c1
14335310c2b391
1517b5d74217c1
hexbefbd7b17d3

13124304050131 has 2 divisors, whose sum is σ = 13124304050132. Its totient is φ = 13124304050130.

The previous prime is 13124304050111. The next prime is 13124304050167. The reversal of 13124304050131 is 13105040342131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13124304050131 - 211 = 13124304048083 is a prime.

It is a super-2 number, since 2×131243040501312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13124304050131.

It is not a weakly prime, because it can be changed into another prime (13124304050111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562152025065 + 6562152025066.

It is an arithmetic number, because the mean of its divisors is an integer number (6562152025066).

Almost surely, 213124304050131 is an apocalyptic number.

13124304050131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124304050131 is an equidigital number, since it uses as much as digits as its factorization.

13124304050131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 13124304050131 its reverse (13105040342131), we get a palindrome (26229344392262).

The spelling of 13124304050131 in words is "thirteen trillion, one hundred twenty-four billion, three hundred four million, fifty thousand, one hundred thirty-one".