Base | Representation |
---|---|
bin | 1011111011111011111100… |
… | …0101101110001001110001 |
3 | 1201110200012012021122000201 |
4 | 2332332333011232021301 |
5 | 3210012112221143142 |
6 | 43525122350115201 |
7 | 2523126105105604 |
oct | 276767705561161 |
9 | 51420165248021 |
10 | 13124331037297 |
11 | 41aaaa77a1287 |
12 | 157b6bbaabb01 |
13 | 74280823b13c |
14 | 33531465433b |
15 | 17b5d99a2ab7 |
hex | befbf16e271 |
13124331037297 has 2 divisors, whose sum is σ = 13124331037298. Its totient is φ = 13124331037296.
The previous prime is 13124331037247. The next prime is 13124331037313. The reversal of 13124331037297 is 79273013342131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12735305646336 + 389025390961 = 3568656^2 + 623719^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124331037297 - 231 = 13122183553649 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124331037247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562165518648 + 6562165518649.
It is an arithmetic number, because the mean of its divisors is an integer number (6562165518649).
Almost surely, 213124331037297 is an apocalyptic number.
It is an amenable number.
13124331037297 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124331037297 is an equidigital number, since it uses as much as digits as its factorization.
13124331037297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 571536, while the sum is 46.
The spelling of 13124331037297 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, thirty-seven thousand, two hundred ninety-seven".
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