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13124335105001 is a prime number
BaseRepresentation
bin1011111011111011111101…
…0101001111001111101001
31201110200012110221021212102
42332332333111033033221
53210012114241330001
643525123013223145
72523126154510031
oct276767725171751
951420173837772
1013124335105001
1141aaaaa01a41a
12157b701331ab5
13742809033773
14335314dd28c1
1517b5da007e6b
hexbefbf54f3e9

13124335105001 has 2 divisors, whose sum is σ = 13124335105002. Its totient is φ = 13124335105000.

The previous prime is 13124335104997. The next prime is 13124335105027. The reversal of 13124335105001 is 10050153342131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12287997419776 + 836337685225 = 3505424^2 + 914515^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124335105001 - 22 = 13124335104997 is a prime.

It is not a weakly prime, because it can be changed into another prime (13124335105901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167552500 + 6562167552501.

It is an arithmetic number, because the mean of its divisors is an integer number (6562167552501).

Almost surely, 213124335105001 is an apocalyptic number.

It is an amenable number.

13124335105001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124335105001 is an equidigital number, since it uses as much as digits as its factorization.

13124335105001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 13124335105001 its reverse (10050153342131), we get a palindrome (23174488447132).

The spelling of 13124335105001 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, one hundred five thousand, one".