Base | Representation |
---|---|
bin | 1011111011111011111101… |
… | …0101001111001111101001 |
3 | 1201110200012110221021212102 |
4 | 2332332333111033033221 |
5 | 3210012114241330001 |
6 | 43525123013223145 |
7 | 2523126154510031 |
oct | 276767725171751 |
9 | 51420173837772 |
10 | 13124335105001 |
11 | 41aaaaa01a41a |
12 | 157b701331ab5 |
13 | 742809033773 |
14 | 335314dd28c1 |
15 | 17b5da007e6b |
hex | befbf54f3e9 |
13124335105001 has 2 divisors, whose sum is σ = 13124335105002. Its totient is φ = 13124335105000.
The previous prime is 13124335104997. The next prime is 13124335105027. The reversal of 13124335105001 is 10050153342131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12287997419776 + 836337685225 = 3505424^2 + 914515^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124335105001 - 22 = 13124335104997 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124335105901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167552500 + 6562167552501.
It is an arithmetic number, because the mean of its divisors is an integer number (6562167552501).
Almost surely, 213124335105001 is an apocalyptic number.
It is an amenable number.
13124335105001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124335105001 is an equidigital number, since it uses as much as digits as its factorization.
13124335105001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 13124335105001 its reverse (10050153342131), we get a palindrome (23174488447132).
The spelling of 13124335105001 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, one hundred five thousand, one".
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