13124335105051 has 4 divisors (see below), whose sum is σ = 13694958370512. Its totient is φ = 12553711839592.

The previous prime is 13124335105027. The next prime is 13124335105153. The reversal of 13124335105051 is 15050153342131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13124335105051 - 2¹⁷ = 13124334973979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124335104998 and 13124335105016.

It is not an unprimeable number, because it can be changed into a prime (13124335105001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285311632696 + ... + 285311632741.

It is an arithmetic number, because the mean of its divisors is an integer number (3423739592628).

Almost surely, 2^{13124335105051} is an apocalyptic number.

13124335105051 is a deficient number, since it is larger than the sum of its proper divisors (570623265461).

13124335105051 is an equidigital number, since it uses as much as digits as its factorization.

13124335105051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 570623265460.

The product of its (nonzero) digits is 27000, while the sum is 34.

Adding to 13124335105051 its reverse (15050153342131), we get a palindrome (28174488447182).

The spelling of 13124335105051 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, one hundred five thousand, fifty-one".