Base | Representation |
---|---|
bin | 1011111011111011111101… |
… | …0110000111001010000001 |
3 | 1201110200012111100221000111 |
4 | 2332332333112013022001 |
5 | 3210012114321142032 |
6 | 43525123022151321 |
7 | 2523126156452515 |
oct | 276767726071201 |
9 | 51420174327014 |
10 | 13124335334017 |
11 | 41aaaaa166496 |
12 | 157b701422541 |
13 | 7428090b3a8b |
14 | 335315052145 |
15 | 17b5da050c47 |
hex | befbf587281 |
13124335334017 has 2 divisors, whose sum is σ = 13124335334018. Its totient is φ = 13124335334016.
The previous prime is 13124335334003. The next prime is 13124335334029. The reversal of 13124335334017 is 71043353342131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13083043468401 + 41291865616 = 3617049^2 + 203204^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124335334017 - 223 = 13124326945409 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124335334057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167667008 + 6562167667009.
It is an arithmetic number, because the mean of its divisors is an integer number (6562167667009).
Almost surely, 213124335334017 is an apocalyptic number.
It is an amenable number.
13124335334017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124335334017 is an equidigital number, since it uses as much as digits as its factorization.
13124335334017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 40.
Adding to 13124335334017 its reverse (71043353342131), we get a palindrome (84167688676148).
The spelling of 13124335334017 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, three hundred thirty-four thousand, seventeen".
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