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13124335341401 is a prime number
BaseRepresentation
bin1011111011111011111101…
…0110001000111101011001
31201110200012111101022010222
42332332333112020331121
53210012114321411101
643525123022245425
72523126156513164
oct276767726107531
951420174338128
1013124335341401
1141aaaaa170a99
12157b701426875
137428090b724b
14335315054adb
1517b5da05301b
hexbefbf588f59

13124335341401 has 2 divisors, whose sum is σ = 13124335341402. Its totient is φ = 13124335341400.

The previous prime is 13124335341391. The next prime is 13124335341413. The reversal of 13124335341401 is 10414353342131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13109475731401 + 14859610000 = 3620701^2 + 121900^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124335341401 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13124335343401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167670700 + 6562167670701.

It is an arithmetic number, because the mean of its divisors is an integer number (6562167670701).

Almost surely, 213124335341401 is an apocalyptic number.

It is an amenable number.

13124335341401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124335341401 is an equidigital number, since it uses as much as digits as its factorization.

13124335341401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 13124335341401 its reverse (10414353342131), we get a palindrome (23538688683532).

The spelling of 13124335341401 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, three hundred forty-one thousand, four hundred one".