Search a number
-
+
13124335403849 is a prime number
BaseRepresentation
bin1011111011111011111101…
…0110011000001101001001
31201110200012111111110210212
42332332333112120031021
53210012114330410344
643525123023450505
72523126160163225
oct276767726301511
951420174443725
1013124335403849
1141aaaaa2039aa
12157b701456a35
137428091097b7
1433531506d785
1517b5da06679e
hexbefbf598349

13124335403849 has 2 divisors, whose sum is σ = 13124335403850. Its totient is φ = 13124335403848.

The previous prime is 13124335403831. The next prime is 13124335403857. The reversal of 13124335403849 is 94830453342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8122112404624 + 5002222999225 = 2849932^2 + 2236565^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124335403849 - 212 = 13124335399753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124335403797 and 13124335403806.

It is not a weakly prime, because it can be changed into another prime (13124335403899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167701924 + 6562167701925.

It is an arithmetic number, because the mean of its divisors is an integer number (6562167701925).

Almost surely, 213124335403849 is an apocalyptic number.

It is an amenable number.

13124335403849 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124335403849 is an equidigital number, since it uses as much as digits as its factorization.

13124335403849 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3732480, while the sum is 50.

The spelling of 13124335403849 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, four hundred three thousand, eight hundred forty-nine".