Base | Representation |
---|---|
bin | 1011111011111100000010… |
… | …0011001101000001010001 |
3 | 1201110200020220101122200211 |
4 | 2332333000203031001101 |
5 | 3210012140004334441 |
6 | 43525125023244121 |
7 | 2523126523312264 |
oct | 276770043150121 |
9 | 51420226348624 |
10 | 13124355543121 |
11 | 420000a609929 |
12 | 157b708149641 |
13 | 74281033b424 |
14 | 3353179d2cdb |
15 | 17b5dbbe3a81 |
hex | befc08cd051 |
13124355543121 has 2 divisors, whose sum is σ = 13124355543122. Its totient is φ = 13124355543120.
The previous prime is 13124355543107. The next prime is 13124355543137. The reversal of 13124355543121 is 12134555342131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12255852698896 + 868502844225 = 3500836^2 + 931935^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124355543121 - 225 = 13124321988689 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124355543181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562177771560 + 6562177771561.
It is an arithmetic number, because the mean of its divisors is an integer number (6562177771561).
Almost surely, 213124355543121 is an apocalyptic number.
It is an amenable number.
13124355543121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124355543121 is an equidigital number, since it uses as much as digits as its factorization.
13124355543121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 216000, while the sum is 40.
The spelling of 13124355543121 in words is "thirteen trillion, one hundred twenty-four billion, three hundred fifty-five million, five hundred forty-three thousand, one hundred twenty-one".
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