Base | Representation |
---|---|
bin | 1011111011111100001011… |
… | …1001000011011111010011 |
3 | 1201110200100122022102020112 |
4 | 2332333002321003133103 |
5 | 3210012230033410213 |
6 | 43525132545231535 |
7 | 2523130511231561 |
oct | 276770271033723 |
9 | 51420318272215 |
10 | 13124394825683 |
11 | 420002a7aa459 |
12 | 157b7193325ab |
13 | 74281851354b |
14 | 33531ccdaa31 |
15 | 17b5e03a2ea8 |
hex | befc2e437d3 |
13124394825683 has 2 divisors, whose sum is σ = 13124394825684. Its totient is φ = 13124394825682.
The previous prime is 13124394825673. The next prime is 13124394825719. The reversal of 13124394825683 is 38652849342131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124394825683 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13124394825623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562197412841 + 6562197412842.
It is an arithmetic number, because the mean of its divisors is an integer number (6562197412842).
Almost surely, 213124394825683 is an apocalyptic number.
13124394825683 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124394825683 is an equidigital number, since it uses as much as digits as its factorization.
13124394825683 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29859840, while the sum is 59.
The spelling of 13124394825683 in words is "thirteen trillion, one hundred twenty-four billion, three hundred ninety-four million, eight hundred twenty-five thousand, six hundred eighty-three".
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