13124404442031 has 4 divisors (see below), whose sum is σ = 17499205922712. Its totient is φ = 8749602961352.

The previous prime is 13124404442003. The next prime is 13124404442033. The reversal of 13124404442031 is 13024440442131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13124404442031 - 2⁷ = 13124404441903 is a prime.

It is a super-2 number, since 2×13124404442031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13124404441983 and 13124404442001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124404442033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187400740336 + ... + 2187400740341.

It is an arithmetic number, because the mean of its divisors is an integer number (4374801480678).

Almost surely, 2^{13124404442031} is an apocalyptic number.

13124404442031 is a deficient number, since it is larger than the sum of its proper divisors (4374801480681).

13124404442031 is an equidigital number, since it uses as much as digits as its factorization.

13124404442031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4374801480680.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 13124404442031 its reverse (13024440442131), we get a palindrome (26148844884162).

The spelling of 13124404442031 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, four hundred forty-two thousand, thirty-one".