Base | Representation |
---|---|
bin | 11101110101110110101000… |
… | …010110011000011000001011 |
3 | 122012200211001210002222010112 |
4 | 131311312220112120120023 |
5 | 114200300444331300204 |
6 | 1143044420422104535 |
7 | 36434035066122125 |
oct | 3565665026303013 |
9 | 565624053088115 |
10 | 131244140103179 |
11 | 38900366619134 |
12 | 12877bb0b7b14b |
13 | 583036688912c |
14 | 245a370a78215 |
15 | 1028e6446826e |
hex | 775da859860b |
131244140103179 has 2 divisors, whose sum is σ = 131244140103180. Its totient is φ = 131244140103178.
The previous prime is 131244140103149. The next prime is 131244140103187. The reversal of 131244140103179 is 971301041442131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131244140103179 is a prime.
It is a super-2 number, since 2×1312441401031792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131244140103149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622070051589 + 65622070051590.
It is an arithmetic number, because the mean of its divisors is an integer number (65622070051590).
Almost surely, 2131244140103179 is an apocalyptic number.
131244140103179 is a deficient number, since it is larger than the sum of its proper divisors (1).
131244140103179 is an equidigital number, since it uses as much as digits as its factorization.
131244140103179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 41.
The spelling of 131244140103179 in words is "one hundred thirty-one trillion, two hundred forty-four billion, one hundred forty million, one hundred three thousand, one hundred seventy-nine".
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