13124421100423 has 4 divisors (see below), whose sum is σ = 13155744301560. Its totient is φ = 13093097899288.

The previous prime is 13124421100391. The next prime is 13124421100429. The reversal of 13124421100423 is 32400112442131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13124421100423 - 2⁵ = 13124421100391 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124421100391 and 13124421100400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124421100429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15661599940 + ... + 15661600777.

It is an arithmetic number, because the mean of its divisors is an integer number (3288936075390).

Almost surely, 2^{13124421100423} is an apocalyptic number.

13124421100423 is a deficient number, since it is larger than the sum of its proper divisors (31323201137).

13124421100423 is an equidigital number, since it uses as much as digits as its factorization.

13124421100423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31323201136.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 13124421100423 its reverse (32400112442131), we get a palindrome (45524533542554).

The spelling of 13124421100423 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twenty-one million, one hundred thousand, four hundred twenty-three".