Base | Representation |
---|---|
bin | 10011000110010011110… |
… | …001000000110010110101 |
3 | 11122110122111011110122021 |
4 | 103012103301000302311 |
5 | 133000341143434331 |
6 | 2442532320233141 |
7 | 163551405663310 |
oct | 23062361006265 |
9 | 4573574143567 |
10 | 1312444124341 |
11 | 466671546a79 |
12 | 19243aa6b7b1 |
13 | 969bc27c41c |
14 | 47746175977 |
15 | 24216673211 |
hex | 13193c40cb5 |
1312444124341 has 16 divisors (see below), whose sum is σ = 1536636544128. Its totient is φ = 1097430969600.
The previous prime is 1312444124293. The next prime is 1312444124351. The reversal of 1312444124341 is 1434214442131.
It is not a de Polignac number, because 1312444124341 - 29 = 1312444123829 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312444124297 and 1312444124306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312444124351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3771286 + ... + 4104568.
It is an arithmetic number, because the mean of its divisors is an integer number (96039784008).
Almost surely, 21312444124341 is an apocalyptic number.
It is an amenable number.
1312444124341 is a deficient number, since it is larger than the sum of its proper divisors (224192419787).
1312444124341 is a wasteful number, since it uses less digits than its factorization.
1312444124341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 347052.
The product of its digits is 36864, while the sum is 34.
Adding to 1312444124341 its reverse (1434214442131), we get a palindrome (2746658566472).
The spelling of 1312444124341 in words is "one trillion, three hundred twelve billion, four hundred forty-four million, one hundred twenty-four thousand, three hundred forty-one".
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