13124442001453 has 4 divisors (see below), whose sum is σ = 13129304709600. Its totient is φ = 13119579293308.

The previous prime is 13124442001439. The next prime is 13124442001469. The reversal of 13124442001453 is 35410024442131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124442001453 - 2⁹ = 13124442000941 is a prime.

It is a super-2 number, since 2×13124442001453² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124442001753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2431350025 + ... + 2431355422.

It is an arithmetic number, because the mean of its divisors is an integer number (3282326177400).

Almost surely, 2^{13124442001453} is an apocalyptic number.

It is an amenable number.

13124442001453 is a deficient number, since it is larger than the sum of its proper divisors (4862708147).

13124442001453 is an equidigital number, since it uses as much as digits as its factorization.

13124442001453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4862708146.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 13124442001453 its reverse (35410024442131), we get a palindrome (48534466443584).

The spelling of 13124442001453 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-two million, one thousand, four hundred fifty-three".