13124450122441 has 4 divisors (see below), whose sum is σ = 14999371568512. Its totient is φ = 11249528676372.

The previous prime is 13124450122409. The next prime is 13124450122519. The reversal of 13124450122441 is 14422105442131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13124450122441 - 2⁵ = 13124450122409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124450122397 and 13124450122406.

It is not an unprimeable number, because it can be changed into a prime (13124450122541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937460723025 + ... + 937460723038.

It is an arithmetic number, because the mean of its divisors is an integer number (3749842892128).

Almost surely, 2^{13124450122441} is an apocalyptic number.

It is an amenable number.

13124450122441 is a deficient number, since it is larger than the sum of its proper divisors (1874921446071).

13124450122441 is an equidigital number, since it uses as much as digits as its factorization.

13124450122441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1874921446070.

The product of its (nonzero) digits is 30720, while the sum is 34.

Adding to 13124450122441 its reverse (14422105442131), we get a palindrome (27546555564572).

The spelling of 13124450122441 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fifty million, one hundred twenty-two thousand, four hundred forty-one".