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13124450122409 is a prime number
BaseRepresentation
bin1011111011111100011000…
…1011111111101010101001
31201110200111111100210002102
42332333012023333222221
53210012333212404114
643525142242343145
72523132052236533
oct276770613775251
951420444323072
1013124450122409
114200058a3872a
12157b73395aab5
13742826b047c2
143353263b2853
1517b5e51772de
hexbefc62ffaa9

13124450122409 has 2 divisors, whose sum is σ = 13124450122410. Its totient is φ = 13124450122408.

The previous prime is 13124450122391. The next prime is 13124450122519. The reversal of 13124450122409 is 90422105442131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8066718998809 + 5057731123600 = 2840197^2 + 2248940^2 .

It is an emirp because it is prime and its reverse (90422105442131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124450122409 - 228 = 13124181686953 is a prime.

It is not a weakly prime, because it can be changed into another prime (13124450112409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562225061204 + 6562225061205.

It is an arithmetic number, because the mean of its divisors is an integer number (6562225061205).

Almost surely, 213124450122409 is an apocalyptic number.

It is an amenable number.

13124450122409 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124450122409 is an equidigital number, since it uses as much as digits as its factorization.

13124450122409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

The spelling of 13124450122409 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fifty million, one hundred twenty-two thousand, four hundred nine".