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13125145043 is a prime number
BaseRepresentation
bin11000011100101000…
…11101000111010011
31020212201021110012002
430032110131013103
5203340014120133
610010221224215
7643152614663
oct141624350723
936781243162
1013125145043
11562589080a
12266370206b
1313122aa71a
148c72241a3
1551c421ce8
hex30e51d1d3

13125145043 has 2 divisors, whose sum is σ = 13125145044. Its totient is φ = 13125145042.

The previous prime is 13125145037. The next prime is 13125145051. The reversal of 13125145043 is 34054152131.

13125145043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (34054152131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13125145043 - 24 = 13125145027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13125144997 and 13125145015.

It is not a weakly prime, because it can be changed into another prime (13125145643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562572521 + 6562572522.

It is an arithmetic number, because the mean of its divisors is an integer number (6562572522).

Almost surely, 213125145043 is an apocalyptic number.

13125145043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125145043 is an equidigital number, since it uses as much as digits as its factorization.

13125145043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 13125145043 its reverse (34054152131), we get a palindrome (47179297174).

The spelling of 13125145043 in words is "thirteen billion, one hundred twenty-five million, one hundred forty-five thousand, forty-three".