Base | Representation |
---|---|
bin | 11000011100101001… |
… | …10110010000010111 |
3 | 1020212201110200110011 |
4 | 30032110312100113 |
5 | 203340030414043 |
6 | 10010223341051 |
7 | 643153524136 |
oct | 141624662027 |
9 | 36781420404 |
10 | 13125248023 |
11 | 5625951118 |
12 | 2663751787 |
13 | 1312315564 |
14 | 8c724d91d |
15 | 51c44259d |
hex | 30e536417 |
13125248023 has 4 divisors (see below), whose sum is σ = 13225440888. Its totient is φ = 13025055160.
The previous prime is 13125247999. The next prime is 13125248053. The reversal of 13125248023 is 32084252131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13125248023 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125248053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50096236 + ... + 50096497.
It is an arithmetic number, because the mean of its divisors is an integer number (3306360222).
Almost surely, 213125248023 is an apocalyptic number.
13125248023 is a deficient number, since it is larger than the sum of its proper divisors (100192865).
13125248023 is a wasteful number, since it uses less digits than its factorization.
13125248023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100192864.
The product of its (nonzero) digits is 11520, while the sum is 31.
The spelling of 13125248023 in words is "thirteen billion, one hundred twenty-five million, two hundred forty-eight thousand, twenty-three".
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