13125254104341 has 32 divisors (see below), whose sum is σ = 19473475799040. Its totient is φ = 8737278030000.

The previous prime is 13125254104301. The next prime is 13125254104373. The reversal of 13125254104341 is 14340145252131.

13125254104341 is a `hidden beast` number, since 1 + 3 + 1 + 252 + 54 + 10 + 4 + 341 = 666.

It is not a de Polignac number, because 13125254104341 - 2¹⁹ = 13125253580053 is a prime.

It is a super-2 number, since 2×13125254104341² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13125254104296 and 13125254104305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125254104301) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 155908326 + ... + 155992488.

It is an arithmetic number, because the mean of its divisors is an integer number (608546118720).

Almost surely, 2^{13125254104341} is an apocalyptic number.

It is an amenable number.

13125254104341 is a deficient number, since it is larger than the sum of its proper divisors (6348221694699).

13125254104341 is an equidigital number, since it uses as much as digits as its factorization.

13125254104341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92614 (or 92608 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 13125254104341 its reverse (14340145252131), we get a palindrome (27465399356472).

The spelling of 13125254104341 in words is "thirteen trillion, one hundred twenty-five billion, two hundred fifty-four million, one hundred four thousand, three hundred forty-one".